Encyclopedia Masses Masses Channel Cost Base Rule Of Channel Cost Premises
ARTICLE 3 claims 2 theorems 1 model
Masses Channel Cost Base Rule Of Channel Cost Premises
A theorem in the Recognition Science library shows that two simple modeling choices force the base cost coefficient to be exactly 2, and that without them the coefficient is free.
The base rule's two premises
The Recognition Science framework models physical structure through a discrete record of recognition events, called a ledger: a bookkeeping system where each entry records a distinction the universe participates in. One of its library's theorems, base_rule_of_channelCostPremises, establishes a precise conditional statement: if two modeling premises hold, then the base cost coefficient is forced to be 2. The first premise is that each configuration degree of freedom costs exactly one rung on the cost ladder. The second is that each gauge channel, a distinction a species participates in, has exactly two sides. The theorem proves that under these two premises, the coefficient multiplying the number of active channel classes is exactly 2, for every fermion.
The theorem is a conditional, not an unconditional derivation. It does not prove that the premises are true; it proves that if they are true, the coefficient follows. The two premises are definitional choices, tagged as MODEL in the framework's own accounting. The theorem itself is a formal consequence, tagged THEOREM, verified in the machine-checked library. The structure ChannelCostPremises packages the two premises as a single object: a channel has two sides, and each degree of freedom costs one rung.
The library also proves the contrapositive in a useful sense. Without the premises, the coefficient is not forced. At a deformation where the coefficient is 4 instead of 2, every banked structure of the table survives, but observable predictions change. This is a separate theorem, channel_cost_independent_without_premises, which shows that the coefficient's value is genuinely load-bearing: it is not a harmless bookkeeping choice. The two premises are what close the base rule, and the theorem shows exactly what hangs on them.
What the theorem does not claim is just as important as what it proves. It does not claim that the two premises are physically necessary. It does not claim that the coefficient 2 is the only possible value. It does not claim that the premises are derived from the framework's forcing chain; they are modeling inputs, not outputs. The theorem's role is narrower and cleaner: given the premises, the coefficient is 2; without them, it is free. That is the whole content, and the library is careful to say so.
THEOREM base_rule_of_channelCostPremises · IndisputableMonolith/Masses/ChannelCost.lean
/-- **Under the two named premises the base rule is forced.** The coefficient is
`rungPerDof * dofOfChannel = 1 * 2 = 2`, closing
`RungBaseBoundary.channel_cost_premise_closes_base`. -/
theorem base_rule_of_channelCostPremises (P : ChannelCostPremises) :
∀ f : Fermion,
(P.rungPerDof * P.dofOfChannel : ℕ) * activeChannelClasses f
= 2 * activeChannelClasses f := by
intro f
rw [P.rungPerDof_eq_one, P.dof_eq_two_sides]
norm_num
MODEL ChannelCostPremises · IndisputableMonolith/Masses/ChannelCost.lean
/-- The two modeling premises under which the base-rule coefficient is derived,
in the pattern of B-22 (`Foundation/GapDerivation.lean`): the per-dof pricing rule
(one rung per configuration degree of freedom, the same rule that prices `E_coh`),
and the channel-as-distinction count (one gauge channel is one distinction the
species participates in, and a distinction has exactly two sides,
`Foundation/BoolFromLogic.lean`). -/
structure ChannelCostPremises where
dofOfChannel : ℕ
rungPerDof : ℕ
dof_eq_two_sides : dofOfChannel = 2
rungPerDof_eq_one : rungPerDof = 1
THEOREM channel_cost_independent_without_premises · IndisputableMonolith/Masses/ChannelCost.lean
/-- **Without the premises, the coefficient is independent.** At deformation `k = 2`
(coefficient 4 instead of 2) every banked structure of the table survives
(`RungBaseBoundary.shiftedRungs_factors`), yet observable predictions change
(`RungBaseBoundary.baseRule_predictions_differ`). -/
theorem channel_cost_independent_without_premises (Z : ℤ) :
(∀ f : Fermion,
shiftedRungs 2 f
= (2 + 2) * activeChannelClasses f + Integers.tau (genOf f).val
+ (if f = Fermion.nu3 then 2 else 0))
∧ predictAt .Lepton (deformedTotal 2 Fermion.e) Z
≠ predictAt .Lepton (deformedTotal 0 Fermion.e) Z :=
⟨shiftedRungs_factors 2, baseRule_predictions_differ 2 (by norm_num) Z⟩
What this page does not claim
The theorem does not prove the two premises are physically true. The theorem does not show the coefficient 2 is the only possible value. The theorem does not derive the premises from the framework's forcing chain.
Verify this page
Every tagged claim above names its theorem. To check one yourself rather than trust this page, elaborate the source module with Lean 4 and audit its axiom basis:
$ lake env lean IndisputableMonolith/Masses/ChannelCost.lean
expected axiom basis: [propext, Classical.choice, Quot.sound] (the Lean kernel's standard three; no RS-specific axioms)
A page whose claims cannot be reproduced this way does not ship. In production, every anchor links to the exact declaration in the public source release, and this block carries the build receipt for the page itself.
Derived articles
This page is generated by a question-recursion engine: the questions its answers raise become the next pages. The current agenda, with open targets marked red:
- What physical argument, if any, selects the two premises over their deformations?
- How does the base cost coefficient 2 feed into the derived particle masses?
- What is the ledger's discrete record in the context of gauge channels?
MACHINE LAYER · GROUNDED CLAIM TABLE · CLICK TO EXPAND
THEOREM base_rule_of_channelCostPremises · IndisputableMonolith/Masses/ChannelCost.lean
/-- **Under the two named premises the base rule is forced.** The coefficient is `rungPerDof * dofOfChannel = 1 * 2 = 2`, closing `RungBaseBoundary.channel_cost_premise_closes_base`. -/ theorem base_rule_of_channelCostPremises (P : ChannelCostPremises) : ∀ f : Fermion, (P.rungPerDof * P.dofOfChannel : ℕ) * activeChannelClasses f = 2 * activeChannelClasses f := by intro f rw [P.rungPerDof_eq_one, P.dof_eq_two_sides] norm_numThe theorem proves that under the two premises, the coefficient multiplying the number of active channel classes is exactly 2, for every fermion. base_rule_of_channelCostPremises · IndisputableMonolith/Masses/ChannelCost.leanMODEL ChannelCostPremises · IndisputableMonolith/Masses/ChannelCost.lean
/-- The two modeling premises under which the base-rule coefficient is derived, in the pattern of B-22 (`Foundation/GapDerivation.lean`): the per-dof pricing rule (one rung per configuration degree of freedom, the same rule that prices `E_coh`), and the channel-as-distinction count (one gauge channel is one distinction the species participates in, and a distinction has exactly two sides, `Foundation/BoolFromLogic.lean`). -/ structure ChannelCostPremises where dofOfChannel : ℕ rungPerDof : ℕ dof_eq_two_sides : dofOfChannel = 2 rungPerDof_eq_one : rungPerDof = 1The two premises are definitional choices, tagged as MODEL in the framework's own accounting. ChannelCostPremises · IndisputableMonolith/Masses/ChannelCost.leanTHEOREM channel_cost_independent_without_premises · IndisputableMonolith/Masses/ChannelCost.lean
/-- **Without the premises, the coefficient is independent.** At deformation `k = 2` (coefficient 4 instead of 2) every banked structure of the table survives (`RungBaseBoundary.shiftedRungs_factors`), yet observable predictions change (`RungBaseBoundary.baseRule_predictions_differ`). -/ theorem channel_cost_independent_without_premises (Z : ℤ) : (∀ f : Fermion, shiftedRungs 2 f = (2 + 2) * activeChannelClasses f + Integers.tau (genOf f).val + (if f = Fermion.nu3 then 2 else 0)) ∧ predictAt .Lepton (deformedTotal 2 Fermion.e) Z ≠ predictAt .Lepton (deformedTotal 0 Fermion.e) Z := ⟨shiftedRungs_factors 2, baseRule_predictions_differ 2 (by norm_num) Z⟩Without the premises, the coefficient is not forced: at a deformation where the coefficient is 4 instead of 2, every banked structure survives, but observable predictions change. channel_cost_independent_without_premises · IndisputableMonolith/Masses/ChannelCost.lean