Encyclopedia Foundation Foundation Recognition Hilbert Space3 Recog Hilbert3 Cert
ARTICLE 3 claims 3 theorems
Foundation Recognition Hilbert Space3 Recog Hilbert3 Cert
A machine-checked certificate records three elementary properties of a cost function; it does not build the Hilbert space its name suggests.
The certification record
In the Recognition Science framework, a cost function assigns a nonnegative price to a comparison. The declaration RecogHilbert3Cert is a formal record, checked by a machine, that three such properties hold for the specific cost defined as Jcost(m/e), where m and e are positive real numbers. The record is a certificate: it packages three proved facts into a single object that other proofs can rely on.
The three facts are elementary. First, when the two inputs are equal, the cost is zero: comparing something to itself costs nothing. Second, for positive inputs, the cost is never negative. Third, a particular constant, phi minus three halves, is positive. The first two are properties of the cost function itself. The third is a statement about the golden ratio phi, which is approximately 1.618, and it simply says this constant is greater than zero.
The name of the declaration suggests a Hilbert space, a complete vector space with an inner product, which is a standard mathematical structure. But the certificate itself does not construct such a space. The docstring records an intention: the space H_RS would be L^2 of a recognition manifold, with a basis indexed by rung and coordinates, and a Hamiltonian built from the cost. None of that is in the Lean code. The certificate proves only the three general facts about the cost function, nothing specific to Hilbert spaces or to any physical system.
What the certificate does establish is a reusable foundation. Because the three facts are proved once and packaged as a structure, any later theorem that needs to know the cost is zero at equality, nonnegative, or that the threshold is positive can cite this certificate instead of reproving those facts. The certificate is a small but sound building block; the Hilbert space it names remains a research note, not a result.
THEOREM domainCost_at_eq · IndisputableMonolith/Foundation/RecognitionHilbertSpace3.lean
theorem domainCost_at_eq (r : ℝ) (h : r ≠ 0) : domainCost r r = 0 := by
unfold domainCost; rw [div_self h]; exact Jcost_unit0
THEOREM domainCost_nonneg · IndisputableMonolith/Foundation/RecognitionHilbertSpace3.lean
theorem domainCost_nonneg (m e : ℝ) (hm : 0 < m) (he : 0 < e) : 0 ≤ domainCost m e := by
unfold domainCost; exact Jcost_nonneg (div_pos hm he)
THEOREM canonicalThreshold_pos · IndisputableMonolith/Foundation/RecognitionHilbertSpace3.lean
theorem canonicalThreshold_pos : 0 < canonicalThreshold := by
unfold canonicalThreshold; linarith [phi_gt_onePointFive]
What this page does not claim
The certificate does not construct the Hilbert space H_RS or any of its basis states. It does not define what m and e mean physically; they are just positive real numbers in the code. It does not prove anything about a Hamiltonian or about the recognition manifold named in the docstring.
Verify this page
Every tagged claim above names its theorem. To check one yourself rather than trust this page, elaborate the source module with Lean 4 and audit its axiom basis:
$ lake env lean IndisputableMonolith/Foundation/RecognitionHilbertSpace3.lean
expected axiom basis: [propext, Classical.choice, Quot.sound] (the Lean kernel's standard three; no RS-specific axioms)
A page whose claims cannot be reproduced this way does not ship. In production, every anchor links to the exact declaration in the public source release, and this block carries the build receipt for the page itself.
Derived articles
This page is generated by a question-recursion engine: the questions its answers raise become the next pages. The current agenda, with open targets marked red:
- What definition of m and e in a physical subject's own terms would turn this certificate into a theorem about that subject?
- How does the full Hilbert space H_RS get constructed from the recognition manifold, if at all?
- What role does the positive threshold phi minus three halves play in later Recognition Science results?
MACHINE LAYER · GROUNDED CLAIM TABLE · CLICK TO EXPAND
THEOREM domainCost_at_eq · IndisputableMonolith/Foundation/RecognitionHilbertSpace3.lean
theorem domainCost_at_eq (r : ℝ) (h : r ≠ 0) : domainCost r r = 0 := by unfold domainCost; rw [div_self h]; exact Jcost_unit0When the two inputs are equal, the cost is zero: comparing something to itself costs nothing. domainCost_at_eq · IndisputableMonolith/Foundation/RecognitionHilbertSpace3.leanTHEOREM domainCost_nonneg · IndisputableMonolith/Foundation/RecognitionHilbertSpace3.lean
theorem domainCost_nonneg (m e : ℝ) (hm : 0 < m) (he : 0 < e) : 0 ≤ domainCost m e := by unfold domainCost; exact Jcost_nonneg (div_pos hm he)For positive inputs, the cost is never negative. domainCost_nonneg · IndisputableMonolith/Foundation/RecognitionHilbertSpace3.leanTHEOREM canonicalThreshold_pos · IndisputableMonolith/Foundation/RecognitionHilbertSpace3.lean
theorem canonicalThreshold_pos : 0 < canonicalThreshold := by unfold canonicalThreshold; linarith [phi_gt_onePointFive]A particular constant, phi minus three halves, is positive. canonicalThreshold_pos · IndisputableMonolith/Foundation/RecognitionHilbertSpace3.lean